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Home » \(A = 1000 \left(1.025\right)^12\) - Get link 4share

\(A = 1000 \left(1.025\right)^12\) - Get link 4share

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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📌 + 3 + 7 = 12

📌 Thus, the sum of the distinct prime factors is \(\boxed{12}\).

📌 Question:** An archaeologist finds two stone tablets with inscriptions totaling 36 symbols. What is the probability that a randomly selected symbol count \( n \) (from 1 to 36, inclusive) is a factor of 36?

📌 First, determine the total number of possible symbol counts: from 1 to 36, so there are 36 possible values.

📌 Next, find how many positive integers \( n \) in this range are factors of 36. Begin with the prime factorization:

📌 = 2^2 \times 3^2

📌 The number of positive factors is:

📌 The factors are: 1, 2, 3, 4, 6, 9, 12, 18, and 36.

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