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Home » A_2 = \frac{\sqrt3}4 \times 12^2 = 36\sqrt3 - Get link 4share

A_2 = \frac{\sqrt3}4 \times 12^2 = 36\sqrt3 - Get link 4share

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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📌 a^3 + b^3 = (a+b)(a^2 - ab + b^2)

📌 We know \( a + b = 10 \) and \( a^2 + b^2 = 58 \). Use the identity:

📌 a^2 + b^2 = (a+b)^2 - 2ab

📌 = 10^2 - 2ab \implies 58 = 100 - 2ab \implies 2ab = 42 \implies ab = 21

📌 Now substitute \( a+b \), \( a^2+b^2 \), and \( ab \) into the sum of cubes formula:

📌 Question:** A cartographer is designing a map transformation function \( T(x) = 3x^2 - 2x + 5 \). If \( x = g(y) = 2y + 1 \), find \( T(g(3)) \).

📌 First, find \( g(3) \):

📌 g(3) = 2(3) + 1 = 7

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