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📅 March 10, 2026 👤 scraface

Mar 10, 2026

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🔥 Popular Posts

Let the base of the original isosceles triangle be \(b\). The area of...
\frac{1}{2} \times b \times h = 48
where \(h\) is the height from the vertex to the base. Using the Pytha...
h = \sqrt{10^2 - \left(\frac{b}{2}\right)^2} = \sqrt{100 - \frac{b^2}{...
Substituting into the area equation:
\frac{1}{2} \times b \times \sqrt{100 - \frac{b^2}{4}} = 48
Solving for \(b\) involves trial or algebraic manipulation, but instea...
h' = \sqrt{100 - \frac{(b+4)^2}{4}}
\frac{1}{2} \times (b + 4) \times h'
\frac{1}{2} \times (b + 4) \times h' - 48

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