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\boxed{\left( -\dfrac43, \dfrac34 \right)} - Get link 4share

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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f(x) = 1 + 2s + \frac{1}{s}
Note $ s = \frac{1}{2} \sin 2x $, and since $ 0 < x < \frac{\pi}{2} $,...
Define $ g(s) = 1 + 2s + \frac{1}{s} $, for $ 0 < s \leq \frac{1}{2} $...
g'(s) = 2 - \frac{1}{s^2}
Set $ g'(s) = 0 \Rightarrow 2 = \frac{1}{s^2} \Rightarrow s^2 = \frac{...
So minimum occurs at endpoint $ s = \frac{1}{2} $:
g\left( \frac{1}{2} \right) = 1 + 2 \cdot \frac{1}{2} + \frac{1}{\frac...
Thus, the minimum value is $ \boxed{4} $.
Question: A philosopher of science considers three unit vectors $ \mat...
Solution: Since $ \mathbf{a}, \mathbf{b}, \mathbf{c} $ are unit vector...

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