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Home » Don’t Miss This Bo6 Easter Egg Hunt—Epic Secrets Uncovered!" - Get link 4share

Don’t Miss This Bo6 Easter Egg Hunt—Epic Secrets Uncovered!" - Get link 4share

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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📌 m(2) = 2(2)^3 - 9(2)^2 + 12(2) - 4 = 16 - 36 + 24 - 4 = 0

📌 So, \( x = 2 \) is a root. Use synthetic division to divide \( m(x) \) by \( x - 2 \):

📌 & 2 & -9 & 12 & -4 \

📌 & & 4 & -10 & 4 \

📌 & 2 & -5 & 2 & 0 \

📌 The quotient is \( 2x^2 - 5x + 2 \). Solve \( 2x^2 - 5x + 2 = 0 \) using the quadratic formula:

📌 x = rac{-(-5) \pm \sqrt{(-5)^2 - 4 \cdot 2 \cdot 2}}{2 \cdot 2} = rac{5 \pm \sqrt{25 - 16}}{4} = rac{5 \pm \sqrt{9}}{4} = rac{5 \pm 3}{

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Question: Compute $ \sum_{k=1}^{50} rac{1}{k(k+2)} $.
Solution: We evaluate the sum:
\sum_{k=1}^{50} rac{1}{k(k+2)}.
We use partial fractions:
rac{1}{k(k+2)} = rac{A}{k} + rac{B}{k+2}.
Multiply both sides by $ k(k+2) $:
= A(k+2) + Bk.
Set $ k = 0 $: $ 1 = A(2) \Rightarrow A = rac{1}{2} $.
Set $ k = -2 $: $ 1 = B(-2) \Rightarrow B = -rac{1}{2} $.
rac{1}{k(k+2)} = rac{1}{2}\left( rac{1}{k} - rac{1}{k+2}

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