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📅 March 9, 2026 👤 scraface

Mar 09, 2026

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x^2 + y^2 + z^2 = 2
Distance from $(1,1,0)$:
\Rightarrow x^2 - 2x + 1 + y^2 - 2y + 1 + z^2 = 2
\Rightarrow (x^2 + y^2 + z^2) - 2x - 2y + 2 = 2
\Rightarrow 2 - 2x - 2y + 2 = 2 \Rightarrow -2x - 2y = -2 \Rightarrow...
Distance from $(1,0,1)$:
\Rightarrow x^2 - 2x + 1 + y^2 + z^2 - 2z + 1 = 2
\Rightarrow (x^2 + y^2 + z^2) - 2x - 2z + 2 = 2
\Rightarrow 2 - 2x - 2z + 2 = 2 \Rightarrow -2x - 2z = -2 \Rightarrow...
From (2) and (3), we have:

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