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Home » f(y) = \frac4(1 + y)y^2. - Get link 4share

f(y) = \frac4(1 + y)y^2. - Get link 4share

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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📌 But in olympiad style, perhaps we find the smallest three-digit number divisible by **at least one**, but thatâs not âandâ.

📌 Alternatively, suppose the problem meant: divisible by **the sum** or **difference**âbut not stated.

📌 Given the constraints, and the only multiple of 7,11,13 in a range is 1001, and itâs four digits, **no** such three-digit number exists.

📌 But this cannot be the intended answer.

📌 Waitâperhaps âdivisible by 7, 11, and 13â means the number is divisible by **each**, but we can scale down? No.

📌 Unless the number is not required to be three-digit, but the context says âthree-digit integer $ z $â.

📌 Thus, the only resolution is that the **least common multiple is 1001**, and since no three-digit number is divisible by all three, the problem may be flawed.

📌 But in educational context, perhaps they meant: divisible by **7** and **11**, or **13**âbut not **and** both.

🔥 Popular Posts

x = rac{6 \pm 2\sqrt{3}}{6} = 1 \pm rac{\sqrt{3}}{3}
Thus, the critical points are:
oxed{1 + rac{\sqrt{3}}{3}, 1 - rac{\sqrt{3}}{3}}
Question:** A quantum machine learning algorithm designer models the p...
Solution:** To verify if \( x = 1 \) is a root of multiplicity greater...
Calculate \( p(1) \):
p(1) = 1^4 - 4 imes 1^3 + 6 imes 1^2 - 4 imes 1 + 1 = 1 - 4 + 6 - 4...
Since \( p(1) = 0 \), \( x = 1 \) is indeed a root. To check the multi...
p'(x) = 4x^3 - 12x^2 + 12x - 4
Now, evaluate \( p'(1) \):

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