h(x) = \frac3x + 5{\sqrt2x + 1} \cdot \frac{\sqrt2x + 1}{\sqrt2x + 1} = \frac{(3x + 5) \sqrt2x + 1}2x + 1

h(x) = \frac3x + 5{\sqrt2x + 1} \cdot \frac{\sqrt2x + 1}{\sqrt2x + 1} = \frac{(3x + 5) \sqrt2x + 1}2x + 1 - Get link 4share

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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