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Home » r = \fracAs = \frac{6x^2\sqrt6}9x = \frac{2x\sqrt6}3 - Get link 4share

r = \fracAs = \frac{6x^2\sqrt6}9x = \frac{2x\sqrt6}3 - Get link 4share

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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Thus, $ x^2 = \boxed{20} $.
Question: Find the largest value of $ x $ that satisfies $ |2x - 5| +...
Solution: We analyze the expression by considering the critical points...
$ x < -3 $:
Then $ 2x - 5 < 0 $, $ x + 3 < 0 $, so:
-(2x - 5) - (x + 3) = -2x + 5 - x - 3 = -3x + 2 = 12 \Rightarrow -3x =...
But $ -\frac{10}{3} < -3 $, so valid.
$ -3 \le x < \frac{5}{2} $:
Then $ 2x - 5 < 0 $, $ x + 3 \ge 0 $, so:
-(2x - 5) + (x + 3) = -2x + 5 + x + 3 = -x + 8 = 12 \Rightarrow -x = 4...

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