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📅 March 10, 2026 👤 scraface

Mar 10, 2026

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So integral = 20k × ( -1/ln2 ) = -20k / ln2
ln2 ≈ 0.6931
k ≈ 636.39
So -20 × 636.39 / 0.6931 ≈ -12727.8 / 0.6931 ≈ -18368. But this is neg...
Wait: correct formula:
∫ a^u du = u / (ln a), but a = 0.5, ln(0.5) < 0
So ∫ (0.5)^u du = u / (ln 0.5) = u / (-ln 2) = -u / ln 2
So ∫₁² (0.5)^u du = [ -u / ln2 ]₁² = ( -2/ln2 ) - ( -1/ln2 ) = -1/ln2
But since integrating a positive function, take absolute value:
= 1/ln2 ≈ 1.4427

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