Solution: Let $ \theta = \arccos\left(\frac1{\sqrt2}\right) $, so $ \cos \theta = \frac1{\sqrt2} $. Then $ \theta = 45^\circ $, and $ \tan \theta = 1 $. The answer is $ \boxed1 $.

Solution: Let $ \theta = \arccos\left(\frac1{\sqrt2}\right) $, so $ \cos \theta = \frac1{\sqrt2} $. Then $ \theta = 45^\circ $, and $ \tan \theta = 1 $. The answer is $ \boxed1 $. - Get link 4share

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Mar 10, 2026

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