Solution: The slope forms a right triangle with opposite side 1 and adjacent side $ \sqrt3 $. Thus, $ \tan \theta = \frac1{\sqrt3} = \boxed{\frac{\sqrt3}3} $.Question: What is the remainder when the sum $ 1^3 + 2^3 + 3^3 + \dots + 10^3 $ is divided by 9?

Solution: The slope forms a right triangle with opposite side 1 and adjacent side $ \sqrt3 $. Thus, $ \tan \theta = \frac1{\sqrt3} = \boxed{\frac{\sqrt3}3} $.Question: What is the remainder when the sum $ 1^3 + 2^3 + 3^3 + \dots + 10^3 $ is divided by 9? - Get link 4share

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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