Solution: Using $\tan(60^\circ) = \frac{\textheight}{\textshadow length}$, we substitute $\tan(60^\circ) = \sqrt3$ and shadow length $5\,\textcm$. Solving for height: $\textheight = 5 \cdot \sqrt3$. Thus, $\boxed{5\sqrt3}$. - Get link 4share