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Home » The smallest number of whole non-overlapping squares needed is \(\boxed20\). - Get link 4share

The smallest number of whole non-overlapping squares needed is \(\boxed20\). - Get link 4share

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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Rewrite 32 as a power of 2: \( 32 = 2^5 \).
So, \( 2^{x+1} = 2^5 \).
Equating the exponents, \( x + 1 = 5 \).
Subtracting 1 from both sides, \( x = 4 \).
#### \( x = 4 \)
Find the area of a circle with a circumference of 31.4 units.
The formula for circumference is \( C = 2\pi r \).
So, \( 31.4 = 2\pi r \).
Solving for \( r \), \( r = rac{31.4}{2\pi} pprox rac{31.4}{6.28} =...
The area \( A = \pi r^2 = \pi imes 5^2 = 25\pi \).

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