Thus \( \phi = k\pi \). Now use \( \cos^2(\phi) = \frac12 \), but \( \cos(k\pi) = \pm 1 \), so \( \cos

Thus \( \phi = k\pi \). Now use \( \cos^2(\phi) = \frac12 \), but \( \cos(k\pi) = \pm 1 \), so \( \cos - Get link 4share

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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