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Home » Time for first segment: \( \frac{150 \text km}{75 \text km/h} = 2 \text hours \) - Get link 4share

Time for first segment: \( \frac{150 \text km}{75 \text km/h} = 2 \text hours \) - Get link 4share

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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t = \frac{-(-4) \pm \sqrt{(-4)^2 - 4 \cdot 3 \cdot 1}}{2 \cdot 3}
t = \frac{4 \pm \sqrt{16 - 12}}{6}
t = \frac{4 \pm \sqrt{4}}{6}
t = \frac{4 \pm 2}{6}
t = \frac{6}{6} = 1 \quad \text{and} \quad t = \frac{2}{6} = \frac{1}{...
Both values satisfy the equation. Thus, the values of \(t\) are:
\boxed{1 \quad \text{and} \quad \frac{1}{3}}
Question:** A sequence of neural response intensities in a human-machi...
We simplify the expression:
a_n = \frac{n^2 + 1}{n + 1}

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