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Home » We square both sides of the given equation: - Get link 4share

We square both sides of the given equation: - Get link 4share

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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To find the remainder of \( v^4 + 3v + 1 \) when divided by \( v^2 + 1...
v^4 + 3v + 1 = (v^2 + 1)Q(v) + R(v),
where \( R(v) \) is the remainder and has degree less than 2, so let \...
Divide the leading term \( v^4 \) by \( v^2 \), giving \( v^2 \).
Multiply \( v^2(v^2 + 1) = v^4 + v^2 \).
Subtract: \( (v^4 + 3v + 1) - (v^4 + v^2) = -v^2 + 3v + 1 \).
Divide \( -v^2 \) by \( v^2 \), giving \(-1\).
Multiply: \(-1(v^2 + 1) = -v^2 - 1\).
Subtract: \((-v^2 + 3v + 1) - (-v^2 - 1) = 3v + 2\).
\boxed{3v + 2}.

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