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Home » z^2 = c \sqrtx^2 + y^2 - rac{(x^2 + y^2)^3/2}c - Get link 4share

z^2 = c \sqrtx^2 + y^2 - rac{(x^2 + y^2)^3/2}c - Get link 4share

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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最初の6項について (\(n = 6\))：
\[ S_6 = 3 \frac{2^6 - 1}{2 - 1} = 3 \times (64 - 1) = 3 \times 63 = 1...
直角三角形の直角を挟む辺の長さが8と15です。斜辺の長さは？
\[ c^2 = a^2 + b^2 \]
ここで、\(a = 8\)，\(b = 15\) です。
\[ c^2 = 8^2 + 15^2 = 64 + 225 = 289 \]
したがって、斜辺 \(c\) は：
\[ c = \sqrt{289} = 17 \]
3x - y = 5
まず、2番目の式から \(y\) を求めます：

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